I figured it out! Sort of on my own, sort of studying how others had “solved” it in different languages (a few of the “solutions” didn’t seem to work). Array Addition I is now my bitch. Also the next 10 easy problems from Coderbyte are on my GitHub. 6 more to go (well 7 actually, I gave up on ArithGeo, but the solving of Array Addition gives me hope that I will figure it out tomorrow). **Problem description:** Using the JavaScript language, have the function ArrayAdditionI(**arr**) take the array of numbers stored in **arr** and return the string **true** if any combination of numbers in the array can be added up to equal the **largest number** in the array, otherwise return the string **false**. For example: if **arr** contains [4, 6, 23, 10, 1, 3] the output should return **true** because 4 + 6 + 10 + 3 = 23. The array will not be empty, will not contain all the same elements, and may contain negative numbers. **And my solution:** (basically grabs the largest value out of a provided array and it runs through all the possible sum combinations of all the other numbers to see if one of those sums equals the largest values)

```
function ArrayAdditionI(arr) {
arr.sort(function(a,b){return a - b})
var largest = arr.pop();
var sum = 0;
for (var i = 0; i < arr.length; i++){
sum += arr[i];
for (var j = 0; j < arr.length; j++){
if (i != j) {
sum += arr[j];
if (sum == largest) {
return true;
}
}
}
for (var k = 0; k < arr.length; k++) {
if (i != k) {
sum -= arr[k];
if (sum == largest) {
return true;
}
}
}
sum = 0;
}
return false;
}
```